Let a, b, c be three distinct real numbers, none equal to one. If the vectors
and
are coplanar, then
is equal to
Text Solution
Verified by ExpertsD
Given that the vectors are coplanar.
That means the determinant is equal to zero.

and 

Expand the determinant along C 1 .
(a - 1) [c(b -1)-(1- c)] + 1[(1 - b) (1 - c)] = 0
c(a - 1) (b - 1) - (a - 1) (1 - c) + (1 - b) (1 - c) = 0
c(l - a) (1 - b) + (1 - a) (1 - c) + (1 - b) (1 - c) +(1 - a)(l - b)(1 - c)
=(l - a)(l - b)(1 - c)
(1 - a) (1 - b) + (1 - a) (1 - c) + (1 - b) (1 - c)
=(1 - a)(l - b)(1 - c)

Hence this is the required option.
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